Upthrust
and Viscosity
·
Density, ρ is
defined as the mass per unit volume. It is measured in
Kgm-3.
Kgm-3.
Density: Mass
per unit volume
Upthrust
·
A fluid will exert a force upward on a body if it
is partly or wholly submerged within it. This is because the deeper into a
fluid you go, the greater the weight of it and so the greater the pressure.
This difference in pressure between the top and the bottom of the object
produces an upward force on it. This is called Upthrust.
·
According to Archimedes' Principle, the upthrust on an
object in a fluid is equal to the weight of the fluid displaced. So
the volume of the object multiplied by the density of the fluid.
Upthrust
= Weight of Fluid Displaced
Viscosity
·
In a fluid, each 'layer' experts a force of friction of
each other 'layer'. This frictional force is also present when solid
object moves through a liquid. This force is termed Viscous
Drag. Viscous Drag is greater in Turbulent Flow than Laminar Flow.
·
The size of the Viscous Drag in a fluid depends on the (coefficient
of)Viscosity of that fluid. Viscosity is given the letter η and
is measured inKgm-2s or Pa s. The greater
the Viscosity, the greater the Viscous Drag.
·
In most liquids, Viscosity decreases as
temperature increases, whereas in most gases, Viscosity
increases as temperature increases. It is therefore important to always
measure the temperature of a fluid when measuring Viscosity.
·
It is possible to calculate the drag force exerted on a spherical
object in a fluid using Stoke's Law:
F = 6πηrv
·
Stoke's Law assumes Laminar Flow, and
so low velocities.
·
In this equation, v represents Terminal
Velocity. This means that the forces acting on the object are balanced.
This means that is it possible to form an equation be equating Weight
with Upthrust and Viscous Drag (or, in the case of Upward Motion,
Upthrust with Weight and Viscous Drag). Laminar flow With
solids, friction is the force that opposes motion between two surfaces pressed
together. In fluid flow, viscosity is the force that opposes motion in and of a fluid. The easiest
case to consider is laminar flow.
Laminar
flow occurs when a fluid can be pictured as split into thin layers which slide
smoothly over each other.
The thin layers (or laminas) are held back by viscous drag between the surfaces of the layers.
The thin layers (or laminas) are held back by viscous drag between the surfaces of the layers.
For example, if
two flat solid plates are separated by a viscous fluid, an external force is
needed to slide the top plate at constant speed over the fixed lower plate.
Viscous drag acts not only between the fluid and the upper plate but also between adjacent laminas of fluid. |
The
velocity of the laminas differs by a small amount from the layers on each side
as shown in the diagram.
The velocity decreases uniformly from the upper plate speed to zero at the lower plate.
The velocity decreases uniformly from the upper plate speed to zero at the lower plate.
Laminar flow of a
fluid in a tube
Laminar flow in a
tube can be thought of as co-axial tubes sliding past each other.
The velocity profile for the sliding tubes has the fluid moving slowly on the outside and quickly at the centre. |
Even
though the fluid elements travel in a straight line, the flow is rotational because
a small paddle wheel placed in the tube (anywhere but the exact centre) will
rotate. The rotation is due to the difference in velocities.
Newton's law of
Viscosity
Shear stress is the tangential force (in the plane of the lamina) divided
by the area across which the force acts (the area vector is at right angles
to the plane of the lamina).
Shear strain is the distance moved in the direction of the force divided by the perpendicular distance that separates the opposing forces producing the "twist". |
For
solids, shear stress divided by shear strain gives an elastic modulus.
For
viscous liquids, since the strain is increasing all the time, shear stress
divided by the rate
of shear
strain gives
the viscosity coefficient.
In
particular, for the simple two flat plates geometry
The
force depends directly on the area of the plates and the velocity
gradient between
the plates. This is known as Newton's
Law of Viscosity. Force/Area has the units of pressure, i.e. Pascal (Pa).
Velocity/distance has the units of s-1. Therefore, the viscosity
coefficient has the unit of Pa.s. There is an older unit called the poise, 1
poise = 0.1 Pa.s.
Viscosity coefficients
for some fluids
Fluid
|
Temperature
|
Coefficient
|
CO2
|
20°C
|
15 μPa.s
|
Air
|
20°C
|
18 μPa.s
|
Petrol
|
20°C
|
290 μPa.s
|
Water
|
90°C
|
320 μPa.s
|
Water
|
20°C
|
1 mPa.s
|
Blood
|
37°C
|
2 mPa.s
|
Motor Oil
|
20°C
|
0.03 Pa.s
|
Motor Oil
|
0°C
|
0.11 Pa.s
|
Glycerine
|
20°C
|
1.5 Pa.s
|
Typical Polymers*
|
Tg+20°C
|
10 GPa.s
|
Tg+10°C
|
100 GPa.s
|
|
Tg
|
100 TPa.s
|
|
Soda Lime Glass
|
800°C
|
1 MPa.s
|
515°C
|
100 TPa.s
|
*Tg:
See below. The glass transition temperature is defined for the situation where
there is a smooth
transition from
liquid to solid. At the glass transition temperature the material is considered
to become solid.
Example
F5
An airtrack supports a cart that rides on a thin cushion of air 1 mm thick and 0.04 m2 in area. The viscosity of air is 18 x 10-6 Pa.s. Find the force required to move the cart at a constant speed of 0.2 m.s-1
An airtrack supports a cart that rides on a thin cushion of air 1 mm thick and 0.04 m2 in area. The viscosity of air is 18 x 10-6 Pa.s. Find the force required to move the cart at a constant speed of 0.2 m.s-1
Viscosity at the Atomic Level
At the
atomic level, viscous movement occurs when tightly
bonded molecular units flow
past each other. For this to occur, there has to be weak bonding between the
units. This means that viscosity is important in materials with secondary
bonding between molecular units. Also, materials with a large number of defects
will have similarly weakened bonding.
Materials with secondary bonding:
Material
|
Bonding
|
polar liquid
(water)
|
Hydrogen
|
molten metals
|
Ion/Electron
|
polymers
|
Van der Waals
|
Viscosity and
Temperature
The bonds between
atoms in the solid state are due to a large negative potential energy and a
small positive kinetic energy.
|
At
absolute zero (0K, -273°C) there is no thermal motion, i.e. no kinetic energy,
to assist bond breaking.
As the temperature increases, atoms are given more and more kinetic energy so the total energy of the bond becomes less negative. The bonds between atoms weaken with increasing temperature.
As the temperature increases, atoms are given more and more kinetic energy so the total energy of the bond becomes less negative. The bonds between atoms weaken with increasing temperature.
When
the potential energy and kinetic become comparable a solid can change phase
into a liquid.
When
the kinetic energy dominates then there can be a change of phase into a gas.
The
phase changes are usually abrupt, but in some situations there can be a gradual
change and a smooth transition between solid and liquid.
Above
1600° SiO2 is a
liquid with its tetrahedral base units in random motion. If liquid SiO2 cools quickly then the tetrahedral units do not have time to
move to their lowest energy configuration and the tetrahedrons are linked in
random orientations by secondary bonds, thus forming a glass. If liquid SiO2 cools slowly then the tetrahedrons can jostle past each other into
their lowest energy configurations and link with long range order to form a
crystal.
The
change to a crystal is abrupt with a sudden increase in the viscosity
coefficient. The change to a glass is smooth with a gradual increase in
viscosity. At some point there will be a large increase in viscosity and this
is called the glass transition temperature (Tg in the above graph) and the material is then said to be a solid.
Polymers and
Temperature
Polymers
are long chains of atoms joined together with primary bonds but cross linked
between chains with secondary bonds. Temperature has a stronger effect on the
secondary bonds than the primary bonds.
At low temperatures,
polymers like most materials, are brittle. There is an elastic region ending
in brittle fracture.
At normal temperatures polymers have a non-linear elastic region with a smaller modulus (slope) and a yield point followed by limited plasticity before fracture. At warm temperatures the modulus decreases further and there is a larger easy glide region due to secondary bonds breaking and reforming. The chains tend to align with the applied stress. At high temperatures there is viscous flow. |
Heavily
cross-linked polymers, like rubber, may have different properties such as
non-linear elasticity and high yield points.
Viscosity and Time
Time is
not usually a factor for solids, but provides opportunities for bond breaking
when secondary bonds are important. If the atoms are moving apart at a
particular instant of time then the probability of the bond between them
breaking is enhanced.
Example
F6
A glass slab at room temperature, with dimensions 140 mm × 60 mm × 20 mm, has a shear force of 8.4 kN across its largest faces. The viscosity of this glass at room temperature is 10+16 Pa.s and the average separation between molecules is 0.5 nm. Find the time for two neighboring molecules to slide past each other.
A glass slab at room temperature, with dimensions 140 mm × 60 mm × 20 mm, has a shear force of 8.4 kN across its largest faces. The viscosity of this glass at room temperature is 10+16 Pa.s and the average separation between molecules is 0.5 nm. Find the time for two neighboring molecules to slide past each other.
Answer
F6
Note
that this is independent of the atom spacing.
Drag Force and Terminal
Velocity
An
object moving through a viscous fluid has a resistivity
drag force exerted on it by the fluid. This prevents the object's velocity
from increasing without limit (e.g. cars, boats) as it eventually reaches the
maximum applied force. It means there is a terminal
speed which
is the maximum speed for the given conditions.
In
general, , where
x starts at 1 for low speeds and increases to 2 ,4 etc for high speeds.
The
drag force is affected by shape and speed,
through the drag coefficient, b and, v.
For a car at
typical speeds drag force is given by:
|
• CD is the drag coefficient produced
by the shape of the car. • A is the "front-on" cross-sectional area. • ρ is the density of the fluid. • v is the speed of the car. |
For
most cars CD lies
between 0.2 and 0.5 (the Model T Ford was 0.7).
Drag coefficients for some passenger vehicles
Vehicle (class)
|
CD
|
CD×A
(m2)
|
VW Polo (class A)
|
0.37
|
0.636
|
Ford Escort
(class B)
|
0.36
|
0.662
|
Opel Vectra
(class C)
|
0.29
|
0.547
|
BMW 520i (class
D)
|
0.31
|
0.649
|
Mercedes 300SE
(class E)
|
0.36
|
0.785
|
Including
drag, the resultant force on a car is given by:
The
initial acceleration causes the speed to increase from zero, which in turn
causes the acceleration to decrease. Equilibrium is achieved when the drag
force equals the force the engine can provide, the acceleration goes to zero
and a constant (terminal) speed is reached.
Stokes' Law and
Terminal Speeds
Stokes
calculated the drag force on a sphere at low speeds as , where η is the
viscosity, r is the radius, and v, is
the speed.
Terminal
speed for a sphere falling under gravity in a medium such as air or water.
As
indicated before, when the acceleration goes to zero, the speed goes to a
constant (terminal) value.
Terminal Speeds in Air
Object
|
Terminal Speed
[m.s-1]
|
95% distance [m]
|
7kg shot put
|
145
|
2500
|
skydiver
|
60
|
430
|
baseball
|
42
|
210
|
tennis ball
|
31
|
115
|
basketball
|
20
|
47
|
ping-pong ball
|
9
|
10
|
1.5mm rain drop
|
7
|
6
|
parachutist
|
5
|
3
|
The
"95% distance" is the distance to achieve 95% of the terminal speed.
Example
F7
An oil drop has a density of 930 kg.m-3. The terminal velocity of a spherical drop of this oil falling in air at 20°C is 0.18 m.s-1. At 20°C, air density is 1.2 kg.m-3 and its viscosity is 18 μPa.s. Find the radius of the droplet.
An oil drop has a density of 930 kg.m-3. The terminal velocity of a spherical drop of this oil falling in air at 20°C is 0.18 m.s-1. At 20°C, air density is 1.2 kg.m-3 and its viscosity is 18 μPa.s. Find the radius of the droplet.
Answer
F7
Poiseuille's Law and
Laminar flow in a tube
The
French prounciation of this "law" is something like
"Pwasweeyer".
Consider
a solid cylinder of viscous fluid, (viscosity η),
flowing inside a hollow cylindrical pipe of length, L, and internal radius, R, as
shown below. The flow is driven by a pressure difference, ΔP, and can be modelled as a number of thin co-axial cylinders
flowing past each other. There will be a stationary thin cylinder at the outer
edge and the maximum speed cylinder will be at the centre. The velocity profile
will be parabolic.
The volume flux
(flow rate) is given by:
|
In this
course you will not be asked to derive this formula. .
• The larger the pressure difference, the greater the flux.
• The larger the cross-sectional area, the greater the flux.
• The shorter the length, the greater the flux.
Note:
blood is a viscous fluid but it does not follow Poiseulle's equation because it
has platelets in its plasma.
Example
F8
A small pipe has an inner radius of 4 mm. A fluid with a viscosity of 4 x 10-3 Pa.s flows through it at a rate of 10-6 m3.s-1. Find the pressure difference across a 2 m length of the pipe.
A small pipe has an inner radius of 4 mm. A fluid with a viscosity of 4 x 10-3 Pa.s flows through it at a rate of 10-6 m3.s-1. Find the pressure difference across a 2 m length of the pipe.
Reynold's number and
Turbulent flow
In
turbulent flow the fluid
paths change abruptly and unpredictably with
time.
This picture on
the right shows water flows from a tap that are laminar on the left and
turbulent on the right.
|
|
This picture on
the right shows cigarette smoke rising. It starts as laminar flow and then
changes to turbulent flow.
|
Poiseuille's
law only holds for laminar flow. For turbulent flow you need to find
experimentally what rules apply to the specific situation.
Reynolds’s number
Reynolds’s
number represents the ratio
of driving force to viscous force.
From
Newton's law of motion, the definition of density and the equation of
continuity, the driving
force on the
fluid is given by:
From
Newton's law of viscosity, the
viscous drag force
is given by:
The
ratio of these gives Reynold's number:
In
turbulent flow, the driving force will dominate and in laminar flow the viscous
force will dominate.
Thus
Reynold's number as a ratio of these, gives an indication as to whether a fluid flow is laminar or turbulent.
A "rule of thumb" for laminar vs turbulent
flow.
NR< 2000
|
Laminar flow
|
2000 <NR< 3000
|
Unstable, may flip between laminar and turbulent
|
NR > 3000
|
Turbulent flow
|
Example
F9
A pipe
with diameter 300mm has water (density 1000 kg.m-3, viscosity 1
mPa.s), flowing through it. Find Reynolds’s number for the flow when there is
a:
(a) flow speed of 3 mm.s-1
(b) flow speed of 30 mm.s-1
(a) flow speed of 3 mm.s-1
(b) flow speed of 30 mm.s-1
Answer
F9
A
ten-fold increase in speed changes the flow from laminar to turbulent.
Summarizing:
Laminar flow occurs
when a fluid can be pictured as split into thin layers which slide smoothly
over each other.
|
|
Laminar flow can
be in planes or cylinders
|
|
Newton's law of
Viscosity:
|
|
Viscosity is
important in materials with secondary bonding between tightly bound molecular
units.
|
|
The bonds between
atoms weaken with increasing temperature.
|
|
Time provides
opportunities for bond breaking.
|
|
Viscous Drag
force for a car at typical speeds
|
|
Stokes' Law:
|
|
Terminal speed
for a sphere falling under gravity:
|
|
Poiseuille's Law:
|
|
Reynold's number:
|
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